Serialize and Deserialize BST
Input: root = [2,1,3]
Output: [2,1,3]Input: root = []
Output: []Solutions
π Python
Last updated
Input: root = [2,1,3]
Output: [2,1,3]Input: root = []
Output: []Last updated
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, x):
# self.val = x
# self.left = None
# self.right = None
# O(N) Solution with pre-order traversal
# first element is the root,
# all elements that are less than root are left part of tree
# bigger is right, process left and right recursively
class Codec:
def serialize(self, root: TreeNode) -> str:
"""Encodes a tree to a single string.
"""
if root is None:
return ""
else:
return str(root.val) + ";" + self.serialize(root.left) + self.serialize(root.right)
def deserialize(self, data: str) -> TreeNode:
"""Decodes your encoded data to tree.
"""
if data == "":
return None
nodes = data.split(';')
root = TreeNode(int(nodes[0]))
root.left = \
self.deserialize(';'.join([n for n in nodes[1:] if len(n) and int(n) < root.val]))
root.right = \
self.deserialize(';'.join([n for n in nodes[1:] if len(n) and int(n) >= root.val]))
return root
# Your Codec object will be instantiated and called as such:
# Your Codec object will be instantiated and called as such:
# ser = Codec()
# deser = Codec()
# tree = ser.serialize(root)
# ans = deser.deserialize(tree)
# return ans