Count and Say
The count-and-say sequence is a sequence of digit strings defined by the recursive formula:
countAndSay(1) = "1"
countAndSay(n)
is the way you would "say" the digit string fromcountAndSay(n-1)
, which is then converted into a different digit string.
To determine how you "say" a digit string, split it into the minimal number of groups so that each group is a contiguous section all of the same character. Then for each group, say the number of characters, then say the character. To convert the saying into a digit string, replace the counts with a number and concatenate every saying.
For example, the saying and conversion for digit string "3322251"
:
Given a positive integer n
, return the nth
term of the count-and-say sequence.
Example 1:
Input: n = 1
Output: "1"
Explanation: This is the base case.
Example 2:
Input: n = 4
Output: "1211"
Explanation:
countAndSay(1) = "1"
countAndSay(2) = say "1" = one 1 = "11"
countAndSay(3) = say "11" = two 1's = "21"
countAndSay(4) = say "21" = one 2 + one 1 = "12" + "11" = "1211"
Constraints:
1 <= n <= 30
Solutions
🧠 Cpp
class Solution
{
string rle(string s)
{
size_t counter = 0;
char current = s.front();
string res;
for(char ch : s)
{
if(ch == current)
counter++;
else
{
res += to_string(counter) + current;
current = ch;
counter = 1;
}
}
//add data from last iteration at the end
return res + to_string(counter) + current;
}
public:
string countAndSay(int n)
{
string res = "1";
//run-length encoding
while(--n)
res = rle(res);
return res;
}
};
Last updated
Was this helpful?