Find the sum of all left leaves in a given binary tree.
3
/ \
9 20
/ \
15 7
There are two left leaves in the binary tree, with values 9 and 15 respectively. Return 24.
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode() : val(0), left(nullptr), right(nullptr) {}
* TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
* TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
* };
*/
class Solution
{
enum Leaf{R, L};
public:
int sumOfLeftLeaves(TreeNode* node, Leaf pos = R)
{
if(!node)
return 0;
if(pos == L && !node->right && !node->left)
return node->val;
return sumOfLeftLeaves(node->right, R) + sumOfLeftLeaves(node->left, L);
}
};