# Find Numbers with Even Number of Digits

## [Find Numbers with Even Number of Digits](https://leetcode.com/problems/find-numbers-with-even-number-of-digits)

Given an array `nums` of integers, return how many of them contain an **even number** of digits.

**Example 1:**

```

Input: nums = [12,345,2,6,7896]
Output: 2
Explanation: 
12 contains 2 digits (even number of digits). 
345 contains 3 digits (odd number of digits). 
2 contains 1 digit (odd number of digits). 
6 contains 1 digit (odd number of digits). 
7896 contains 4 digits (even number of digits). 
Therefore only 12 and 7896 contain an even number of digits.
```

**Example 2:**

```

Input: nums = [555,901,482,1771]
Output: 1 
Explanation: 
Only 1771 contains an even number of digits.
```

**Constraints:**

* `1 <= nums.length <= 500`
* `1 <= nums[i] <= 10^5`

## Solutions

### 🧠 Cpp

```cpp
#include <limits>

class Solution
{
public:
    int findNumbers(vector<int>& nums)
    {
        int res = 0;
        for(int num : nums)
        for(int i = 1, is_even = 1;
            i < std::numeric_limits<int>::max();
            i*=10, is_even=!is_even)
        {
            if(num/i == 0)
            {
                if(is_even)
                    res++;
                break;
            }

        }

        return res;
    }
};
```


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