Backspace String Compare
Given two strings S
and T
, return if they are equal when both are typed into empty text editors. #
means a backspace character.
Note that after backspacing an empty text, the text will continue empty.
Example 1:
Input: S = "ab#c", T = "ad#c"
Output: true
Explanation: Both S and T become "ac".
Example 2:
Input: S = "ab##", T = "c#d#"
Output: true
Explanation: Both S and T become "".
Example 3:
Input: S = "a##c", T = "#a#c"
Output: true
Explanation: Both S and T become "c".
Example 4:
Input: S = "a#c", T = "b"
Output: false
Explanation: S becomes "c" while T becomes "b".
Note:
1 <= S.length <= 200
1 <= T.length <= 200
S
andT
only contain lowercase letters and'#'
characters.
Follow up:
Can you solve it in
O(N)
time andO(1)
space?
Solutions
🧠 Cpp
class Solution
{
public:
string translate(const string &inputS)
{
string S = inputS;
for(int i = 0; i < S.size(); ++i)
{
if(S[i] == '#')
{
if(i == 0)
{
S.erase(i,1);
i--;
}
else
{
S.erase(i-1,2);
i-=2;
}
}
}
return S;
}
bool backspaceCompare(string S, string T)
{
return translate(S) == translate(T);
}
};
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